What mass of calcium
chloride will be produced
from 4.09 g of HCI
reacting with Ca(OH),?
123
moles

6.22g of CaCl₂

Explanation:

Mass of HCL = 4.09g

Mass of CaCl₂ =

equation of reaction

2HCl + Ca(OH)₂ → CaCl₂ + 2H₂O

From equation of reaction, 2 moles of HCl produces 1 mole of CaCl₂

2(36.5)g of HCl = 111g of CaCl₂

73g of HCl will produce 111g of CaCl₂

4.09g of HCl will produce = x

73g of HCl = 111g of CaCl₂

4.09g of HCl = x

Cross multiply and solve for x

X = (111 * 4.09) / 73

X = 6.219g of CaCl₂ = 6.22g of CaCl₂

4.09g of HCl will produce 6.22g of CaCl₂

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