A 475 ml sample of a gas was collected at room temperature of 23.5 °C and a pressure of

756 mm Hg. Calculate the volume of the gas if the conditions were altered to 10.0 °C and a

pressure of 722 mm Hg.

The volume when the conditions were altered is 0.5109 L or 510.9 mL

Explanation:

Using the general gas equation,

P1 V1 / T1 = P2 V2 / T2

where;

P1 = 756 mmHg

V1 = 475 ml = 0.475 L

T1 = 23.5°C = 23.5 + 273K = 275.5 K

P2 = 722 mm Hg

T2 = 10°C = 10 + 273 K = 283 K

V2 = ?

Rearranging to make V2 the subject of the formula, we obtain:

V2 = P1 V1 T2 / P2 T1

V2 = 756 * 0.475 * 283 / 722 * 275.5

V2 = 101, 625.3 / 198911

V2 = 0.5109 L or  510.9 mL

for points guys

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .