2Al(s)+ 3Pb(N03) 2(aq) 2Al(N03)3(aq) + 3Pb (s)How many molecules of Pb(N03) 2 are used in the reaction? How many oxygen atoms are used in the reaction? How many moles of Al(N03)3 are formed? What is the mole ratio of Pb(N03) 2 to Al(N03)3?

A. 1.806x10^24 molecules of Pb(NO3)2

B. 18 oxygen atoms.

C. 2 moles of Al(NO3)3.

D. The mole ratio of Pb(N03)2 to Al(N03)3 is 3 : 2

Explanation:

The balanced equation for the reaction is given below:

2Al(s) + 3Pb(NO3)2(aq) —> 2Al(NO3)3(aq) + 3Pb (s)

A. Determination of the number molecules of Pb(NO3)2 used in the reaction. This is illustrated below.

From the balanced equation above, 3 moles of Pb(NO3)2 were used in reaction.

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules. This means that 1 mole of Pb(NO3)2 contains 6.02x10^23 molecules.

Now, if 1 mole of Pb(NO3)2 contains 6.02x10^23 molecules,

then, 3 moles of Pb(NO3)2 will contain = 3 x 6.02x10^23 = 1.806x10^24 molecules.

Therefore, 1.806x10^24 molecules of Pb(NO3)2 is used in the reaction.

B. Determination of the number of oxygen atom used in the reaction.

This is illustrated below:

To obtain the number of oxygen atom used in the reaction, we simply do a head count of the oxygen atom in the reactant.

The reactant containing oxygen is Pb(NO3)2 and there are 3 moles of it according to the balanced equation.

There are a total of 18 oxygen atom in 3 moles of Pb(NO3)2. Therefore, 18 oxygen atoms are used in the reaction.

C. Determination of the number of mole of Al(NO3)3 formed.

From the balanced equation above, 2 moles of Al(NO3)3 are formed

D. Determination of the mole ratio of Pb(N03)2 to Al(N03)3

From the balanced, 3 moles of Pb(N03)2 reacted and 2 moles of Al(N03)3 are produced.

Therefore, the mole ratio of Pb(N03)2 to Al(N03)3 is 3 : 2

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