Students working in lab use 52.3g of CaCl2 to make a solution. When the solution is brought to a final volume of 800. mL, what is the concentration?

A. 0.139 M
B. 0.153 M
C. 0.588 M
D. 0.632 M

The answer is C: .588 M

Explanation:

[CaCl2] = mols CaCl2/Liters of solution

molar mass of CaCl2 = 110.98 g/ 1 mole   (from periodic table)

800 mL/1000 mL = .8 Liters of solution

1)

52.3g CaCl2/ 110.98g = .47 mole

2)

.47 mole/.8 L = .589 M

So the answer is C

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