Calculate the number of moles of water produced when 3.3 mol of cu(no3)2 are
formed in the reaction

3 Cu(s) + 8 HNO3(aq) = 3 Cu(NO3)2(s) + 2NO(g) + 4H2O(l)

3 moles Cu(NO3)2 4 moles H2O
3.3 moles Cu(NO3)2 ( moles H2O)

moles H2O = 3.3 x 4 / 3

moles H2O = 13.2 / 3

= 4.4 moles of H2O

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