The equation for the complete combustion of propene, c3h6, is shown below.
2c3h6 (g) + 9o2 (g) → 6co2 (g) + 6h2o (l)
which mixture, when ignited, will lead to incomplete combustion and the formation of co (g)?

a. 2.0 dm3 of propene and 10.0 dm3 of oxygen
b. 0.5 dm3 of propene and 2.3 dm3 of oxygen
c. 1.0 dm3 of propene and 4.0 dm3 of oxygen
d. 3.0 dm3 of propene and 14.0 dm3 of oxygen

i think the answer is c but i am not sure as to why. any is greatly appreciated.

. 1.0 dm3 of propene and 4.0 dm3 of oxygen

Explanation:

From the question, two volumes of propene reacts with nine volumes of oxygen. This implies that one volume of propene should react with 4.5 volumes of oxygen.

In the option stated as the correct answer, the volume of oxygen reacted is less than the stoichiometric volume of oxygen that will completely react with the given volume of propene to give a complete reaction.

Hence the combustion of propene is incomplete in this case and CO is formed.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3