What is the concentration (molarity) of NaOH if 29.39 mL of the solution is neutralized by 31.46 mL of 2.67 M HCL

0.083

Explanation:

Explanation:

We're asked to find the molar concentration (molarity) of the HCl solution, given some titration measurements.

Let's first write the chemical equation for this neutralization reaction:

NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)

Since we're given the molarity and volume of the NaOH solution used, we can calculate the moles be using the molarity equation:

mol solute=(molarity)(L soln)

=(0.1molL)(0.0332L)=0.00332 mol NaOH

Since all the coefficients in the chemical equation are 1, the relative number of moles of HCl used is also 0.00332 mol.

Finally, let's use the molarity equation again to find the molarity of the HCl solution (given the volume of NaOH soln is 40 mL, which must be in liters when using molarity equations):

molarity=mol soluteL soln

=0.00332lmol HCl0.040lL=0.083M

it means there are 3 atoms of oxygen