A chemistry student mixes 25 milliliters of 3.0 M hydrochloric acid (HCl) with excess sodium hydroxide. The chemicals react according to this chemical equation:

HCl + NaOH → NaCl + H2O.

If the volume of the resulting solution is 68 milliliters, what is the concentration of sodium chloride?

1.1 mol/liter

Explanation:

You would use the M1V1 = M2V2 equation to solve this.

We know M1 is 3.0 M, V1 is 25 milliliters, and V2 is 68 milliliters. We need to find M2.

To find M2, first plug in what you know.

(3.0 M)(25 mL) = M2(68 mL)

Then, divide everything by 68 mL to get M2 by itself

Your answer should be a quite large decimal but I rounded it to 1.1 mol/liter.

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2