What volume of 0.250 mol/L sulfuric acid, H2SO4(aq) is needed to react completely with 37.2 mL of 0.650 mol/L potassium hydroxide, KOH(aq)?

d. 48.4 ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is KOH.

We are given:

Putting values in above equation, we get:

Thus volume of 0.250 mol/L sulfuric acid needed is 48.4 ml

5.6⋅10−^19  j

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