If you want to produce 11 moles of NH3, how much H2 do you need?

33 g of H2

Explanation:

N2 + 3 H2 -> 2 NH3

3 mol H2 -> 2 mol NH3

             x -> 11 mol NH3

x= (11 mol NH3 * 3 mol H2)/ 2 mol NH3

x= 16.5 mol H2

1 mol H2    -> 2 g

16.5 mol H2 ->x

x= (16.5 mol H2 * 2 g)/ 1 mol H2

x= 33 g

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)