Calculate the amount of heat gained when one 250 gram bottle is heated from 25oC to 30oC. The specific heat of water is 4.18 J/goC

The amount of heat gained is 5225 J

Explanation:

The specific heat of a substance is the quantity or amount of heat required to change the temperature of a unit mass of the substance by 1.

Thus,

         Q = mcΔθ

where: Q is the quantity of heat required, m is the mass of the substance, c is the specific heat capacity of the substance and Δθ is the change in temperature of the substance.

From the question, given that: m = 250 g, initial temperature = 25, final temperature = 30 and specific heat of water = 4.18 J/g.

So that; the quantity of heat, Q, required is;

         Q = 250 × 4.18 × (30 - 25)

             = 250 × 4.18 × 5

            = 5225 Joules

⇒     Q = 5225 J

Therefore, the amount of heat gained is 5225 J.

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