A gas has a volume of 1.8Lat−26◦Cand 147 kPa. At what temperature would the gas occupy 1.33 L at 217 kPa?

At temperature of 269 K the gas would occupy 1.33 L at 217 kPa

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 147 kPa

= final pressure of gas = 217 kPa

= initial volume of gas = 1.8 L

= final volume of gas = 1.33 L

= initial temperature of gas =

= final temperature of gas = ?

Now put all the given values in the above equation, we get:

Thus at 269 K temperature the gas would occupy 1.33 L at 217 kPa

idk what the question is about