How would you solve this?
"Calculate the amount of energy transferred if only 650.50 grams of sulfur trioxide (SO3) gas were produced. (Remember the ∆H = -396.8 kJ is part of the balanced equation)"
balanced equation: 2 SO2 (g) + O2(g) ⇌ 2 SO3 (g) ∆H = -396.8 kJ

1.6×10^3 KJ

Explanation:

We must first calculate the number of moles corresponding to 650.50g of sulphur trioxide.

Number of moles = mass of sulphur trioxide/ molar mass of sulphur trioxide

Molar mass of sulphur trioxide= 80.066 g/mol

Given mass of sulphur trioxide= 650.50g

Number of moles = 650.50g / 80.066 g/mol

Number of moles = 8.124 moles of sulphur trioxide

Now from the balanced reaction equation;

Formation of 2 moles of sulphur trioxide evolves 396.8KJ of energy.

Therefore formation of 8.124 moles of sulphur trioxide will evolve;

8.124moles × 396.8 KJ /2 moles = 1611.8KJ or 1.6×10^3 KJ

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

hypostyle hall;