A gas has an initial volume of 3.0 L with a pressure of 0.62 atm. What will be the new pressure if the volume changed to 1.0 L?

The new pressure will be 1.86 atm.

Explanation:

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide less times per unit time against them. This means that the pressure will be less because it represents the frequency of gas strikes against the walls. In this way pressure and volume are related, determining Boyle's law.

Boyle's law says that at constant temperature, the volume of a fixed mass of gas is inversely proportional to the pressure it exerts:

P*V=k

To determine the change in pressure or pressure during a transformation to constant pressure, the following expression is applied:

P1*V1=P2*V2

In this case:

P1= 0.62 atmV1= 3 LP2= ?V2= 1 L

Replacing:

0.62 atm* 3L= P2* 1 L

Solving:

P2= 1.86 atm

The new pressure will be 1.86 atm.

Answeramino acids;

First up write the aim
then write the materials reqd.
then the procedure which you follow
then observation
then conclusion
then you can write lab safety rules or precautions(you can avoid if u want).
lemme' give an example
aim: to observe the double displacement reaction
materials reqd: bacl2 and na2so4, test tubes and a dropper
procedure:
1. take bacl2 in a test tube and na2so4 in the other.
2. then pour bacl2 into na2so4 solution.
3. observe
observation:
you will see that a white precipitate is formed called baso4. along with that common salt or nacl is formed.
the equation is
bacl2+na2so4=baso4+2nacl
conclusion:
a double displacement reaction is observed.
hope it