How much heat will be transferred when 5.81g of graphite reacts with excess H2 according to the following equation

6c(graphite) + 3H2 → C6H6 delta H rxn =49.03 kj/molrxn

What mass of graphite must be burned to release 255kj of energy

65uuyhjghj8ykitdyidii

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

i believe the answer is three water molecules