Perform the following calculations then use the Molarity PhET simulation to check answers.

What is the molarity of a 0.400 L solution containing 0.700 moles of Cobalt (II) Chloride?

How many moles of Potassium Permanganate are in 350.0 mL of 0.50 M KMnO4 (aq)?

How many liters of 3.0 M Potassium Chromate solution will contain 2.0 moles of K2CrO4 ?

a = 1.75M

b = 0.175moles

c = 0.67L

Explanation:

Molarity of a substance is the number of moles present in 1L of a solution.

a). 0.7 moles is present in 0.4L

X moles is present in 1L

0.7moles = 0.4L

X moles = 1L

X = 1.75M

The molarity of the solution is 1.75M

b). 0.5moles is present in 1L

X moles will be present in 0.35L

X = (0.5 × 0.35) / 1 = 0.175moles

0.175 moles will be present in 0.35L of the solution

c). 3.0moles is present in 1L

2 moles will be present in how many L

3.0moles = 1L

2.0moles = xL

X = (2.0 / 3.0) / 1

X = 0.67L

2 moles is present in 0.67L of the solution