Quien y en que cantidad sera el reactivo limite, si utilizamos 125 g de ácido, H (CH3COO) y 275 g de hidróxido , Al(OH)3

The limiting reactant is acetic acid. All 125 g will react.  

Explanation:

1. Assemble the information

We will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.  

Mᵣ:                 60.05            78.00

                3CH₃COO-H + Al(OH)₃ ⟶ (CH₃COO)₃Al + 3H₂O

Mass/g:           125               275  

2. Calculate the moles of each reactant

3. Calculate the moles of (CH₃COO)₃Al from each reactant

i think it is true since you can test the answer and can use observations to complete it.