Chemistry, 23.05.2020 06:03 shannaslaughter28
420 Liters of Chlorine gas at a constant Temperature has a Pressure of 46.3 kPa. We need to determine the pressure in kPa of the gas if its Volume changes to 70 liters. We will start by defining the variables. Answer "u" for the question mark or what you are trying to find.
What is the value for V1?
What is the value for P1?
What is the value for V2?
What is the value for P2?
What is the Pressure in kPa when the volume is changed to 70L?
Answers: 3
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Consider the reduction reactions and their equilibrium constants. cu+(aq)+e−↽−−⇀cu(s)pb2+(aq)+2e−↽−−⇀pb(s)fe3+(aq)+3e−↽−−⇀fe(=6.2×108=4.0×10−5=9.3×10−3 cu + ( aq ) + e − ↽ − − ⇀ cu ( s ) k =6.2× 10 8 pb 2 + ( aq ) +2 e − ↽ − − ⇀ pb ( s ) k =4.0× 10 − 5 fe 3 + ( aq ) +3 e − ↽ − − ⇀ fe ( s ) k =9.3× 10 − 3 arrange these ions from strongest to weakest oxidizing agent.
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420 Liters of Chlorine gas at a constant Temperature has a Pressure of 46.3 kPa. We need to determin...
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