What mass of potassium chlorate is needed to produce 8.50 mol of oxygen? 2KCIO3 →
2KCl +302

694.2915 grams of potassium chlorate is needed to produce 8.50 mol of oxygen

Explanation:

It is possible to apply the following rule of three: if by stoichiometry 3 moles of O₂ are produced by 2 moles of KCIO₃, when reacting 8.5 moles of O₂, how many moles of KClO₃ are necessary?

moles of KClO₃= 5.67

To know the amount of mass present in 5.67 moles of the compound, it is necessary to know the molar mass, that is, the amount of mass that a substance contains in one mole. Being:

The molar mass of the compound is:

KClO₃= 39 g/mole + 35.45 g/mole + 3* (16 g/mole)= 122.45 g/mole

Then you can apply the following rule of three: if in 1 mole of the compound there are 122.45 grams, in 5.67 moles how much mass is there?

mass= 694.2915 grams

694.2915 grams of potassium chlorate is needed to produce 8.50 mol of oxygen

aquifers are bounded above and below by impermeable rock. the driving force of groundwater movement in confined aquifers is pressure, rather than gravity.

football

explanation:

because it is