At a certain temperature, 0.4011 mol of N2 and 1.621 mol of H2 are placed in a 2.00 L container. N2(g)+3H2(g)↽−−⇀2NH3(g) N 2 ( g ) + 3 H 2 ( g ) ↽ − − ⇀ 2 NH 3 ( g ) At equilibrium, 0.1001 0.1001 mol of N2 N 2 is present. Calculate the equilibrium constant, c K c . c= K c =