For the reaction 2H₂(g) + O₂(g) → 2H₂O(g), what volume of water vapor can be made from 100 grams of oxygen gas and an excess of hydrogen at STP? Please show work.

140 L

Explanation:

Step 1: Write the balanced equation

2 H₂(g) + O₂(g) → 2 H₂O(g)

Step 2: Calculate the moles corresponding to 100 g of oxygen

The molar mass of oxygen is 32.00 g/mol.

Step 3: Calculate the moles of water vapor formed

The molar ratio of oxygen to water vapor is 1:2.

Step 4: Calculate the volume corresponding to 6.26 moles of water vapor

1 mole of any ideal gas under STP has a volume of 22.4 L.

yes they ca   is ur ansswerrr

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-