How many joules of heat energy are required to raise the temperature of
100 grams of water from 21°C to 23°C?

836.8J

Explanation:

Heat energy = ?

Mass = 100g

Initial temperature (T1) = 21°C

Final temperature (T2) = 23°C

Specific heat capacity of water (c) = 4.184J/g°C

To solve this question, we'll need to use the formula for calculating heat energy of a substance.

Q = mc∇t

Q = heat energy of substance

M = mass of substance

C = specific heat capacity of substance

∇t = change in temperature = T2 - T1

Q = 100 × 4.184 × (23 -21)

Q = 418.4 × 2

Q = 836.8J

The heat energy required to raise 100g of water from 21°C to 23°C is 836.8J

the answer is d : ) have a good da

the tides are influenced by both the moon and the sun, it's easy to see that when the sun lines up with the moon and the earth, as during a new moon or full moon, the tidal effect is increased. these are known as spring tides, named not for the season, but for the fact that the water "springs" higher than normal. on the other hand, if the sun and the moon are 90 degrees apart in relation to an observer on earth as during the first quarter moon or third quarter moon, then high tides are not as high as they normally would be. this is because despite its greater distance, the sun's mass allows it to exert enough gravitational force on the oceans that it can negate some of the effects of the moon's pull. this phenomenon of lower high tides is called a neap tide. if you need more information on this topic visit moonconnection.com.