Calvin is setting up a model of the solar system. He positions a cardboard sun at one end of a school hallway and Pluto at the other end, 20 m away.
Calvin knows that Pluto is 39.5 AU from the sun and Jupiter is 5.27 AU from the sun
In order to make his model scale, how many meters from the cardboard sun should Calvin place Jupiter? (record your answer to two decimal places or nearest hundredth)

  2.67 m

Explanation:

We can write the proportion several ways. One of them is ...

  (model to Jupiter)/(Jupiter distance) = (model to Pluto)/(Pluto distance)

  (model to Jupiter)/5.27 = 20 m/39.5 . . . . . fill in the numbers

  (model to Jupiter) = 20 m(5.27/39.5) ≈ 2.67 m

The model of Jupiter should be placed 2.67 meters from the sun.

on passing the small ampere of electric current through the tube made of ar and hg of cfl generates uv rays which excites the fluorescent and thus emits the high radiation by consumption of just 5- 12 w in comparison to incandescent light which requires more power such as around 40 - 55 w to lighten.

moreover the life span of fluorescent or cfl is around 8000 h whereas the life span of incandescent is around 1200 h

hence, the building installed with incandescent lights bears more electricity bill.