Which formula equation represents the burning of sulfur to produce sulfur dioxide?

Upper S (s) plus upper O subscript 2 (g) right arrow with delta above upper S upper O subscript 2 (g).

2 upper H subscript 2 upper s (s) plus 3 upper 0 subscript 2 (g) right arrow 2 upper H subscript 2 upper O (l) plus 2 upper S upper 0 subscript 2 (g).

4 upper F e upper S subscript 2 plus 11 upper O subscript 2 right arrow 2 upper F e subscript 2 upper O subscript 3 plus 8 upper S upper O subscript 2.

2 upper S upper O subscript 2 (g) plus upper O subscript 2 (g) right arrow with upper V subscript 2 upper O subscript 5 above arrow 2 upper S upper O subscript 3 (g).

Upper S (s) plus upper O subscript 2 (g) right arrow with delta above upper S upper O subscript 2 (g).

The reaction is given as follows:-

Sulphur = S

Oxygen =

Sulfur dioxide =

So the equation is as follows:-

The correct option is option A. Upper S (s) plus upper O subscript 2 (g) right arrow with delta above upper S upper O subscript 2 (g).

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S(s) + O2(g) --> SO2(g)

Upper S (s) plus upper O subscript 2 (g) right arrow with delta above upper S upper O subscript 2 (g).

Explanation:

The reaction is given as;

Sulfur + oxygen --> Sulphur dioxide

Sulphur = S

Oxygen = O2

Sulfur dioxide = SO2

So we have;

S(s) + O2(g) --> SO2(g)

The crrect option is option A. Upper S (s) plus upper O subscript 2 (g) right arrow with delta above upper S upper O subscript 2 (g).

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.