What is the molarity of a solution that contains 1.724 moles of H2SO4 in 2.50 L of solution? Show all your work.

ANSWER:
calculate the # of moles of solute mol H2SO4=1.724 mol
l SOln=2.50l
m=1.724 mol H2SO4 =0.690 m H2SO4/2.50 l SOln

0.690 molar H 2 SO 4  or sulfuric acid

Explanation:

Molarity (M) =  1.724 mol  H 2 SO 4 / 2.50 L  =  0.6896 mol  H 2 SO 4 /L  =  0.690 mol H 2 SO 4 /L

(due to three significant figures in 2.50 L.)

The container for this solution would be labeled  0.690 M H 2 SO 4  and would be called  0.690 molar H 2 SO 4  or sulfuric acid.

The container for this solution would be labeled  0.690 M H 2 SO 4

and would be called  0.690 molar H 2 SO 4  or sulfuric acid.