What is E∘cell for a galvanic cell constructed from aluminum and silver electrodes? Report your answer with three decimal places. Half Reaction E∘ (V) Mn2+(aq)+2e−⟶Mn(s) −1.185 Zn(OH)2(s)+2e−⟶Zn(s)+2OH−(aq) −1.245 Zn2+(aq)+2e−⟶Zn(s) −0.7618 Al3+(aq)+3e−⟶Al(s) −1.662 Mg2+(aq)+2e−⟶Mg(s) −2.372 Ba2+(aq)+2e−⟶Ba(s) −2.912 K+(aq)+e−⟶K(s) −2.931 Ag+(aq)+e−⟶Ag(s) +0.7996 Au3+(aq)+3e−⟶Au(s) +1.498 Provide your answer below:

Explanation:

When the galvanic cell is formed with the electrode Al and Ag , following half cell reaction is possible

Al  = Al⁺³  + 3e  ( At anode )

3Ag⁺ + 3e  =  3Ag .   ( At cathode )

Ecell  = Ecathode - Eanode

=  .7996 - ( - 1.662 )  [ values taken from the chart given ]

= .7996 + 1.662

= 2.4616

= 2.462 V .

the correct option is c.

isotopes refers to different forms of the same element with the same atomic number but different mass number as a result of difference in their neutron numbers. isotopes have different relative atomic mass but share the same chemical properties.