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Consider the following system at equilibrium where H° = 10.4 kJ, and Kc = 1.80×10-2, at 698 K. 2HI(g) H2(g) + I2(g) When 0.40 moles of H2(g) are added to the equilibrium system at constant temperature: The value of Kc The value of Qc Kc. The reaction must run in the forward direction to restablish equilibrium. run in the reverse direction to restablish equilibrium. remain the same. It is already at equilibrium. The concentration of I2 will
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Consider the following system at equilibrium where H° = 10.4 kJ, and Kc = 1.80×10-2, at 698 K. 2HI(g...
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