After 56 days, a 4.0-g sample of phosphorus-32 contains only 0.25 g of isotope. Based on this data,

what is the half-life of phosphorus-32?

324 hours (13.5 days)

Explanation:see attached photo

THE HALF LIFE OF PHOSPHORUS-32 ISOTOPE IS 14 DAYS.

Explanation:

Using the Nerst equation of half life;

t1/2 = t * in(2) / in (No/Nt)

where;

t1/2 = half life = the unknown

t = elapsed time = 56 days

No= initial mass of the sample = 4.0 g

Nt = final mass of the sample = 0.25 g

Substituting the values into the equation, we have;

t1/2 = 56 * Ln2  / Ln ( 4/0.25)

t1/2 = 56 * 0.6932 / Ln (16)      

t1/2 = 56 * 0.6932 / 2.7726      

t1/2 = 38.8192 / 2.7726

t1/2 = 14.001 days.

t1/2 = 14 days.

The half life of the phosphorus- 32 would be 14 days

samuel de champlain. in 1608, king henry iv sponsored pierre dugua, sieur de mons and samuel de champlain as founders of the city of quebec with 28 men. this was the second permanent french settlement in the colony of canada.