In which location would a free neutron from a decaying U-235 atom be most likely to cause another atom to go split?

A. In a sample of naturally occurring uranium

B. In a sample of enriched uranium

C. In a sample of rock or soil

D. In the Sun’s core

E. In a distant star

The correct answer is option B

B. In a sample of enriched uranium

Explanation:

Nuclear fission is a nuclear reaction whereby large nucleus of an atom is break down into smaller parts lighter nuclei or daughter nuclei and release large amount of energy, due to the large amount of energy there are alot of heat released.

During the process large nucleous is bombarded by the neutrons, as a result of this the nucleous becomes disintegrated because it's unstable and their is production of lighter nuclei as well as neutrons and energy.

When the U -235 particles are compacted together there result a high energy neutron which can bombard another Uranium - 235 molecule in the region. uranium is enriched with more of the fissile uranium isotope, then when it is enriched it can be used to make atomic reactors and explosives like bombs.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer