What are the IUPAC names of the following compounds?
a, manganesse dioxed
b, mercurous chloride
c, ferric nitrate
d, titanium tetrachloride
e, cupric bromide

a. Manganese(IV) oxide

b. Mercury(I) chloride

c.  Iron(III) nitrate

d. Titanium(IV) chloride

e. Copper(II) bromide

Explanation:

The IUPAC nomenclature is regulated by International Union of Pure and Applied Chemistry which is used in organic chemistry for naming of the organic chemical compounds.

a. Manganese(IV) oxide is IUPAC name of manganesse dioxed . It is an inorganic compound having the formula MnO2.

b. Mercury(I) chloride is IUPAC name of mercurous chloride . It is also known as the mineral calomel and have a chemical formula Hg2Cl2.

c. Iron(III) nitrate is IUPAC name of ferric nitrate . It have a chemical formula Fe(NO₃)₃.

d. Titanium(IV) chloride is IUPAC name of titanium tetrachloride - .  It have a chemical formula TiCl4.

e. Copper(II) bromide is IUPAC name of cupric bromide with chemical formula CuBr2 or Br2Cu.

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

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