Relacione el punto de ebullición del agua y la acetona (propanona), con la facilidad de a evaporación de estas sustancias (volatilidad), considerando las fuerzas intermoleculares.

Here's what I get  

Explanation:

1. Water

The O-H bond in water is highly polar.

It has about one-third ionic character.

The partially-positive H atoms and partially negative O atoms strongly attract each other  by hydrogen bonds.

It takes a large amount of energy to separate the water molecules from each other.

Thus, the boiling point of water is relatively high (100 °C).

2. Acetone

The C=O bond in acetone is much less polar.

It is less than 20 % ionic.

The dipole-dipole attractions in acetone are much weaker than the hydrogen bonds in water.

It takes much less energy to separate the acetone molecules from each other.

Thus, even though the molar mass of acetone is more than three times that of water, the boiling point of acetone is only 56 °C.

chemistry sucks a**

explanation: