The mass of a compound is taken 5 times with the following results: 26.6mg, 26.3mg, 26.2mg, 26.4mg, and 26.1mg. If the true mass is 25.6mg, what is the percent relative error for this set of data? Round to the nearest hundredth of a percent.

2.813%

Explanation:

First we must take the average of the five mass measurements

Average value= sum of all five trials/ 5= 26.6 + 26.3 + 26.2 + 26.4 +26.1 /3 = 26.32mg

Now, we have been provided the accurate mass of the compound in the question as 25.6mg

Remember that relative percent error = Average value of measurement - True value of measurement / true value×100

Hence we have;

Percent error=

26.32 - 25.6/25.6 ×100

Percent error= 2.813%

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.

i think its 5049.

i hope this !