Chemistry, 05.06.2020 02:05 Randomkid0973
The growth of bacteria X-II can be described by a simple Monod equation with μmax = 0.8 1/h and KM = 4 g/dm3, Yp/c = 0.2 g/g, and Ys/c = 2 g/g. The process is carried out in a CSTR in which the feed rate is 1000 dm3/h at a substrate concentration of 10 g/dm3.
a. What size fermentor is needed to achieve 90% conversion of the substrate? What is the exiting cell concentration?
b. Determine the washout dilution rate and the dilution rate at which the cell production rate is a maximum.
Answers: 2
Chemistry, 22.06.2019 14:30
Consider the reduction reactions and their equilibrium constants. cu+(aq)+e−↽−−⇀cu(s)pb2+(aq)+2e−↽−−⇀pb(s)fe3+(aq)+3e−↽−−⇀fe(=6.2×108=4.0×10−5=9.3×10−3 cu + ( aq ) + e − ↽ − − ⇀ cu ( s ) k =6.2× 10 8 pb 2 + ( aq ) +2 e − ↽ − − ⇀ pb ( s ) k =4.0× 10 − 5 fe 3 + ( aq ) +3 e − ↽ − − ⇀ fe ( s ) k =9.3× 10 − 3 arrange these ions from strongest to weakest oxidizing agent.
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Chemistry, 22.06.2019 23:10
Amines are good nucleophiles, even though they are neutral molecules. how would the rate of an sn2 reaction between an amine and an alkyl halide be affected if the polarity of the solvent is increased? amines are good nucleophiles, even though they are neutral molecules. how would the rate of an reaction between an amine and an alkyl halide be affected if the polarity of the solvent is increased? because both reactants in the rate-limiting step are neutral, the reaction will be faster if the polarity of the solvent is increased. because both reactants in the rate-limiting step are neutral, the reaction will be slower if the polarity of the solvent is increased. because both reactants in the rate-limiting step are neutral, the reaction will occur at the same rate if the polarity of the solvent is increased. request answer
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Chemistry, 23.06.2019 08:00
The biosphere of the earth is made up of . a. inorganic b. organic
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The growth of bacteria X-II can be described by a simple Monod equation with μmax = 0.8 1/h and KM =...
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