Calculate the mean free path of electrons in a metal, such as silver, at room temperature form heat capacity and heat conduction measurements. Take EF ¼ 5 eV, K ¼ 4:29 102 J/s m K, and Cel v ¼ 1% of the lattice heat capacity. (Hint: Remember that the heat capacity in (21.8) is given per unit volume!)

= 4 * 10-8    = 400 Angstrom

Explanation:

EF = 5 eV, K = 4.29 x 102 J/(s m K), and Cvel = 1% of the lattice heat capacity

K= 1/3 (Cv)*v*l

v is fermi velocity which is equal to

after putting mass of electron as and we get

is 1% of lattice heat capacity

Heat Capacity of Aluminium is

Density =

For  lattice heat capacity you need to use the heat capacity for alimunium given  and then multiply with density to get per unit volume term

Heat Capacity per unit volume =   *

Cv = 1% of heat capacity per unit volume

Putting values in this equation K= 1/3 (Cv)*v*l

  = 400 Angstrom

the correct answer would be d. hope this !