3. The volume of a gas is reduced from 4 L to 0.5 L while the temperature is held constant. How does the gas pressure change?

The new pressure is 8 times the original pressure.

Explanation:

Data obtained from the question include:

Initial volume (V1) = 4L

Final volume (V2) = 0.5L

Initial pressure (P1) = P

Final pressure (P2) =..?

The new pressure can be obtained by using the Boyle's law as shown below:

P1V1 = P2V2

P x 4 = P2 x 0.5

Divide both side by 0.5

P2 = P x 4 / 0.5

P2 = 8P

Therefore, the new pressure is 8 times the original pressure.

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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