How many moles of NaOH will be required to produce 375.4 g of any Na2S04

5.28 moles of NaOH.

Explanation:

Step 1:

Determination of the number of mole in

375.4 g of any Na2S04.

Molar mass of Na2SO4 = (2x23) + 32 + (16x4) = 142g

Mass of Na2SO4 = 375.4g

Number of mole of Na2SO4 =..?

Mole = Mass /Molar Mass

Number of mole of Na2SO4 = 375.4/142 = 2.64 moles

Step 2:

The balanced equation for the reaction.

H2SO4 + 2NaOH —> Na2SO4 + 2H2O

Step 3:

Determination of the number of mole of NaOH needed for the reaction.

From the balanced equation above,

2 moles of NaOH reacted to produce 1 mole of Na2SO4.

Therefore, Xmol of NaOH will react to produce 2.64 moles of Na2SO4 i.e

Xmol of NaOH = 2 x 2.64

Xmol of NaOH = 5.28 moles

Therefore, 5.28 moles of NaOH is needed for the reaction.

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