¿Cuántos moles hay en 101,64 g de (NH4)²SO⁴?

0.77 moles

Explanation:

Here, we want to calculate the number of moles in 101.64 g of ammonium sulphate.

Mathematically, this is equal to mass of ammonium sulphate divided by the molar mass of ammonium sulphate

The molar mass of ammonium sulphate is calculated below as follows; 2(14 + 1 (4)) + 32 + 4(16) = 132 g/mol

Hence , number of moles = 101.64/132 = 0.77 moles

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the answer is barium and copper bromide