What is the volume of a 4.0M solution that contains 374 grams of KNO3?'

0.93L

Explanation:

We'll begin by calculating the number of mole of present 374g of KNO3. This is illustrated below:

Mass of KNO3 = 374g

Molar mass of KNO3 = 39 + 14 + (16x3) = 101g/mol

Number of mole of KNO3 =..?

Mole = Mass /Molar Mass

Number of mole of KNO3 = 374/101 = 3.7 moles

Now, we can calculate the volume of the solution as follow:

Mole of KNO3 = 3.7 moles

Molarity = 4M

Volume =..?

Volume = mole /Molarity

Volume = 3.7/4

Volume = 0.93L

Therefore, the volume of the solution is 0.93L

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