When potassium chromate (K2CrO4) is added to a solution containing 0.500 g silver nitrate (AgNO3), solid silver chromate (Ag2CrO4) is formed. a) Determine the theoretical yield.

Theoretical Yield = 0.4882 grams

Explanation:

Potassium Chromate = K2CrO4 Molar mass: 194.1896 g/mol

Silver Nitrate = AgNO3 Molar mass: 169.87 g/mol

Silver(I) Chromate = Ag2CrO4 Molar mass: 331.73 g/mol

Potassium Nitrate = KNO3  Molar mass: 101.1032 g/mol

K2CrO4 + 2AgNO3 = Ag2CrO4 + 2KNO3

Potassium Chromate + Silver Nitrate = Silver(I) Chromate + Potassium Nitrate

Ratio 1:2 = 1:2

0.5g AgNO3

AgNO3 Molar mass: 169.87 g/mol

2AgNO3 = 339.74grams

0.5/339.74 = 0.0014717

Ag2CrO4 Molar mass: 331.73 g/mol

0.4882 grams

Theoretical Yield = 0.4882 grams

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

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