Calculating pH DETERMINE THE PH OF EACH SOLUTION
» [H] = 1 x 10-9M
pH =
» POH = 3
pH =
» [OH ) = 1 x 10-2 M
pH =
» POH = 7
pH =

The answer to your question is given below

Explanation:

1. Data obtained from the question include:

Hydrogen ion concentration, [H+] = 1x10^-9M

pH =..?

pH = - log [H+]

pH = - log 1x10^-9

pH = 9

2. Data obtained from the question include:

pOH = 3

pH =.?

Recall:

pH + pOH = 14

pH + 3 = 14

Collect like terms

pH = 14 - 3

pH = 11

3. Data obtained from the question include:

Hydroxide ion concentration, [OH-] = 1x10^-2M

pH =..?

First, we shall determine the pOH. This is illustrated below

pOH = - Log [OH-]

pOH = - Log 1x10^-2

pOH = 2

Finally, we can obtain the pH as follow:

pH + pOH = 14

pOH = 2

pH + 2 = 14

Collect like terms

pH = 14 - 2

pH = 12

4. Data obtained from the question include:

pOH = 7

pH =.?

Recall:

pH + pOH = 14

pH + 7 = 14

Collect like terms

pH = 14 - 7

pH = 7

beta decay is the answer

explanation: no but i do not usually comment