2H3PO4 + 3Na2SO4 → 2Na3PO4 + 3H2SO4 Molar masses:
Sodium sulfate = 142.05 g/mol
Phosphoric acid = 98 g/mol
Sodium phosphate = 163.94 g/mol
Sulfuric acid = 98.09 g/mol

a) If 1.08 g of sodium sulfate reacts with an excess of phosphoric acid, how much sulfuric acid is produced?

b) If 0.726 g of sulfuric acid is produced in the laboratory experiment, what is the percent yield of sulfuric acid?

To get the molarity, you divide the moles of solute by the litres of solution.

Molarity

=

moles of solute

litres of solution

For example, a 0.25 mol/L NaOH solution contains 0.25 mol of sodium hydroxide in every litre of solution.

To calculate the molarity of a solution, you need to know the number of moles of solute and the total volume of the solution.

To calculate molarity:

Calculate the number of moles of solute present.

Calculate the number of litres of solution present.

Divide the number of moles of solute by the number of litres of solution.

Explanation:

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.