How many grams of aluminum oxide would be produced from the reaction of 0.25 grams of aluminum with excess oxygen gas?

0.472 grams of aluminum oxide would be produced from the reaction of 0.25 grams of aluminum with excess oxygen gas.

Explanation:

First of all, you should know that the balanced reaction that occurs:

4 Al + 3 O₂ → 2 Al₂O₃

Then, by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts are produced in moles:

Being:

The molar mass of the compounds participating in the reaction is:

Then, by stoichiometry of the reaction, the following amounts of mass react and are produced:

Now it is possible to apply the following rule of three: if 108 grams of Al produce 204 grams of Al₂O₃, 0.25 grams of aluminum how much mass of Al₂O₃ will it produce?

mass of Al₂O₃=0.472 grams

0.472 grams of aluminum oxide would be produced from the reaction of 0.25 grams of aluminum with excess oxygen gas.

the child will have heterozygous dominant chromosomes as characters of his father are dominant over the characters of his mother.

the child is heterozygous