1. What Volume of HCl is generated if 3.44 g of Cl2 are reacted at STP? 2. What volume does 4.87 mol of Kr have at STP? 3. What pressure of HCl is generated if 3.44 g of Cl2 are reacted in 4.55 L at 455 K?

1. 2.17 dm^3

2. 109.1 dm^3

3. 0.398 atm

Explanation:

1. Considering the equation of the reaction;

Number of moles of chlorine gas in 3.44 g= 3.44/2(35.5)= 0.0485 moles

Since we can see from the equation that

1 mole of chlorine gas yields 2(22.4) dm^3 of HCl

0.0485 moles of chlorine gas yields 0.0485 moles × 2(22.4)dm^3/1= 2.17 dm^3

2. Note that 1 mole of Kr occupies 22.4 dm^3

Therefore 4.87 moles of Kr will occupy 4.87 × 22.4 dm^3/1 = 109.1 dm^3

3. From PV= nRT

n= 0.0485 moles

V= 4.55 L

T= 455 K

P= the unknown

R= 0.082 atm dm^3K-1mol-1

P= nRT/V

P= 0.0485 moles × 0.082 atm dm^3K-1mol-1 × 455/4.55

P= 0.398 atm

1) volume of HCl = 2.17 L HCl

2) volume of Kr = 109.09 L

3) Pressure of HCl = 0.796 atm

Explanation:

Step 1: Data given

Mass of Cl2 : 3.44 grams

Molar mass Cl2 = 70.9 g/mol

STP = 1atm and 273 K

Step 2: The balanced equation

H2(g) + Cl2(g) → 2HCl(g)

Step 3: Calculate moles of Cl2

Moles Cl2 = mass/ molar mass Cl2

Moles Cl2 = 3.44 grams / 70.9 g/mol

Moles Cl2 = 0.0485 moles

Step 4: Calculate moles HCl

For 1 mol H2 we need 1 mol Cl2 to produce 2 moles HCl

For 0.0485 moles Cl2 we'll have 2*0.0485 = 0.097 moles HCl

Step 5: Calculate volume of HCl

For 1 mol we have 22.4 L

For 0.097 moles we have 22.4 * 0.097 = 2.17 L HCl

Step 1: Data given

Moles of Kr = 4.87 moles

STP = 1 mol, 1atm and 273 K and 22.4 L

Step 2: Calculate volume at STP

1 mol has a volume of 22.4 L

4.87 moles has a volume of 22.4 L * 4.87 = 109.09 L

Step 1: Data given

Mass of Cl2 : 3.44 grams

Molar mass Cl2 = 70.9 g/mol

Volume = 4.55 L

Temperature = 455 K

Step 2: The balanced equation

H2(g) + Cl2(g) → 2HCl(g)

Step 3: Calculate moles of Cl2

Moles Cl2 = mass/ molar mass Cl2

Moles Cl2 = 3.44 grams / 70.9 g/mol

Moles Cl2 = 0.0485 moles

Step 4: Calculate moles HCl

For 1 mol H2 we need 1 mol Cl2 to produce 2 moles HCl

For 0.0485 moles Cl2 we'll have 2*0.0485 = 0.097 moles HCl

Step 5: Calculate pressure of HCl

p*V = n*R*T

⇒with p = the pressure of HCl = TO BE DETERMINED

⇒with V = the volume = the volume of HCl = 4.55 L

⇒with n = the moles of HCl = 0.097 moles

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 455 K

p = n*R*T / V

p = (0.097 moles * 0.08206L*atm/mol*K * 455 K) / 4.55 L

p = 0.796 atm

samuel de champlain. in 1608, king henry iv sponsored pierre dugua, sieur de mons and samuel de champlain as founders of the city of quebec with 28 men. this was the second permanent french settlement in the colony of canada.

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