A. Consider four different samples: aqueous LiI, molten LiI, aqueous AgI, and molten AgI. Current run through each sample produces one of the following products at the cathode: solid lithium, solid silver, or hydrogen gas. Match each sample to its cathodic product. B. Consider four different samples: aqueous NaBr, molten NaBr, aqueous NaF, and molten NaF. Current run through each sample produces one of the following products at the anode: liquid bromine, fluorine gas, or oxygen gas. Match each sample to its anodic product.

Explanation:

At the cathode

In case of molten AgI

Silver  will be collected

In case of molten LiI

lithium will be collected

in case of aqueous LiI,

hydrogen gas will be collected as reduction potential of H⁺ is more than Li⁺

in case of aqueous AgI,

Silver will be obtained at cathode because reduction potential of silver is more than H⁺

At the Anode  

In case of molten NaBr  

Bromine   will be collected

In case of molten NaF

Fluorine  will be collected

in case of aqueous NaBr ,

Bromine  will be collected as reduction potential of Br⁻ is less than O⁻²

in case of aqueous NaF ,

oxygen will be obtained  because reduction potential of F⁻  is more than O⁻² .

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.