Calculate the ionic strength of0.0082M NaOH?0.0002M La(IO3)3?Find the concentration of I– in 0.010 M AgNO3 saturated with AgI. Include activity coefficients in your solubility-product expression. The Ksp of AgI is 8.3× 10–17. A table of activity coefficients at various ionic strengths can be found here. C. What is the activity coefficient for each ion at the given ionic strength?Hg22 (μ = 0.005 M)?Sc3 (μ = 0.1 M)?Dy3 (μ = 0.1 M)?(CH3CH2)3NH (μ = 0.05 M)?

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.