Please help! An atom's electron configuration ends with 3p3. If another atom has nine more electrons, what would be the continuation of the electron configuration? A)3p^6 4s^2 3d^4 B) 3p^3 4s^2 3d^7 C)3p^6 3d^4 4s^2 D) 3p^3 3d^7 4s^2

Answer;

343  so B

Explanation;

Orbitals. Orbitals (s, p, d, f, g).

S-orbital two electrons

P-orbital six electrons

D-orbital 10 electrons

Electron fill as so =  1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p

Start 3p3

After adding 1 electron 4s1

Then 4s2

Then 3d1 etc 3d2, 3d3, 3d4, 3d5, 3d6, 3d7

pie chart because it is in percents ( % )