A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.62 g of water at 52.3 oC in an insulated container. clear = 0.128 J/g oF; water = 4.18 J/goC. What is the final temperature of both the weight and the water at thermal equilibrium

The final temperature of both the weight and the water at thermal equilibrium is .

Explanation:

The given data is as follows.

mass = 7.62 g,          

Let us assume that T be the final temperature. Therefore, heat lost by water is calculated as follows.

       q =    

          =

Now, heat gained by lead will be calculated as follows.

       q =  

           =

According to the given situation,

     Heat lost = Heat gained

=

        T =

Thus, we can conclude that the final temperature of both the weight and the water at thermal equilibrium is .

i think the answer is terrae but not 100 percent sure. ▓▬▬ §

the answers are

c and c