what radius (mm) must a steel (iron) ball bearing have if it is to have a mass of 3.25g? density of iron = 7.86g/cm3 V=4/3 pie r3

Radius of the steel ball is 4.6mm

Explanation:

Hello,

To find the radius of the steel, we'll have to calculate it from it's volume which can be gotten from the density of the material.

Data;

Mass = 3.25g

Density = 7.86g/cm³

Density = mass / volume

Volume = mass / density

Volume = 3.25 / 7.86

Volume = 0.413cm³

Volume of a steel = 4/3πr³

0.413 = 4/3 × π × r³

0.413 = 1.33 × 3.14 × r³

0.413 = 4.1762r³

r³ = 0.413 / 4.1762

r³ = 0.099

Take the cube root of both sides

r = 3√(0.099)

r = 0.46cm

From metrics table

1cm = 10mm

0.46cm = x mm

x = (0.46 × 10)

x = 4.6mm

The radius of the steel ball is 4.6mm

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).