2-methyl-2-hexanol was prepared by reacting an alkene with either hydroboration-oxidation or oxymercuration-reduction. Draw the structure of the alkene that was used to prepare the alcohol in highest yield. You do not have to consider stereochemistry.

See the explanation

Explanation:

In this question, we have to synthesize a molecule in which the "OH" group is placed in the most substituted carbon. Therefore we have to use a markovnikov reaction to the synthesis. The hydroboration is anti-markovnikov and the oxymercuration-reduction is markovnikov, therefore the oxymercuration-reduction is our best choice.

Now, the double bond can be placed in different places. Because the "OH" would be added in the tertiary carbon of the double bond. So, we can use 2-methylhex-1-ene or 2-methylhex-2-ene.

See figure 1.

I hope it helps

zfoods? ok, pressure is used to keep the heat inside and to keep the food perfect.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.