When hydrocarbons are burned in a limited amount of air, both COCO and CO2CO2 form. When 0.450 gg of a particular hydrocarbon was burned in air, 0.467 gg of COCO, 0.733 gg of CO2CO2, and 0.450 gg of H2OH2O were formed. Part A What is the empirical formula of the compound

0

explanation:

488479

rvmoo+478)9.68

the answer is   c.) 1575 j.

explanation:

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24